Solving a Trigonometry Problem with a Missing 90-Degree Angle

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The discussion revolves around solving a trigonometry problem that lacks a clearly defined 90-degree angle where line h meets the base. Participants agree that the problem cannot be solved without assuming this angle is 90 degrees. After confirming this assumption, the solution is found to be 3.3. The conversation highlights the ease of finding the answer compared to the time spent discussing the problem. Overall, the key takeaway is the necessity of the 90-degree assumption for solving the trigonometric issue.
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The Attempt at a Solution


I'm not sure where to start and the book doesn't show a 90 degree angle on the lower region where h meets the base. Can someone nudge me in the right direction please?[/B]
 
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It isn't solvable unless you assume the line h meets the base at 90 degrees.
 
Nathanael said:
It isn't solvable unless you assume the line h meets the base at 90 degrees.

That's kinda what I was thinking. Thanks for confirming that.
 
All done. The answer is 3.3.
Took more time to post this thread then it did to solve. XD

Thanks again nathanael
 
There is also this solution: :wink:
findX.jpg
 
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I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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