Solving an Equation: Rearranging Numbers Around

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Homework Statement


Okay, yesterday in class my teacher gave me this identity e^{i\pi }+1=0
and she wants me to rearrange the numbers around, so I can get this i^{i}= e^{-\frac{\pi}{2}}


Homework Equations

and

The Attempt at a Solution


I know that if Isolate the 1 to the other side and take the square root of each sides I will have this \sqrt{e^{i\pi }}= \sqrt{-1}
But this is the question what do I do after that ?
 
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xvtsx said:

Homework Equations

and

The Attempt at a Solution


I know that if Isolate the 1 to the other side and take the square root of each sides I will have this \sqrt{e^{i\Pi }}= \sqrt{-1}
But this is the question what do I do after that ?

Do you know another way to write

\sqrt{e^{i \pi}}?

Do you know another way to write

\sqrt{-1}?
 
Hi xvtsx! :smile:

(have a pi: π and try using the X2 tag just above the Reply box :wink:)

Raise each side of your last equation to the power of i. :smile:
 
Hmm.. do I raise to the power of i after I change the square root for \frac{1}{2} and multiple it with iπ ?
 
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(what happened to that π i gave you? :redface:)

Yes, (eiπ/2)i = … ? :smile:
 
sorry for the pi part, but I use the latex editor and it only gaves that one xD.. thanks by the way. :)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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