Solving an Inequality to Determine profit margin

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The discussion focuses on determining the values of x that yield a positive average profit based on the given revenue and cost equations. The profit equation derived is P(x) = R(x) - C(x) = -x^2 + 6x - 5. It is established that average profit is positive when x is between 1 and 5, but confusion arises regarding the condition for x > 5. A participant points out that at x = 6, revenue is less than cost, indicating a loss rather than profit. The conversation highlights the need for clarity on the conditions for achieving a positive average profit.
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Revenue Equation: R(x)=-x^2+10x Cost Equation: C(x)= 4X+5
Average profit= profit equation, P(x)/x

therefore p(x)= R(x)-C(x)=-x^2+6x-5

(-x^2+6x-5)/x=(-1(x-5)(x-1))/x, I then found that x is positive between 1 and 5, therefore average profit is positive in that range, however, the answer is if x>5, where did I go wrong?

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I don't see you've done anything wrong so far. You gave the answer. But what is the question??
 
simply, what values of x will produce a positive average profit? I have gotten three questions which I believe to be right wrong in a row now, I believe the answers are off :)
 
PhysicsAdvice said:
simply, what values of x will produce a positive average profit? I have gotten three questions which I believe to be right wrong in a row now, I believe the answers are off :)

They must be. At x=6 I get R=24 and C=29. That doesn't look profitable to me.
 

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