Solving Bernoulli Problems Homework: Pressure Differential Question

  • Thread starter Thread starter mujadeo
  • Start date Start date
  • Tags Tags
    Bernoulli
AI Thread Summary
The discussion revolves around solving a Bernoulli problem involving a horizontal hose and a nozzle. The velocity of water in the hose is calculated using the equation A1V1 = A2V2, yielding a result of 8.61 m/s. However, the user struggles with calculating the pressure differential between the hose and the nozzle. They attempt to apply Bernoulli's equation but arrive at an incorrect pressure differential of 634.934 Pa. A suggestion is made to ensure the density (rho) is included in the calculations for accuracy.
mujadeo
Messages
103
Reaction score
0

Homework Statement



A long horizontal hose of diameter 3.8 cm is connected to a faucet. At the other end, there is a nozzle of diameter 1.8 cm. Water squirts from the nozzle at velocity 38 m/sec. Assume that the water has no viscosity or other form of energy dissipation.


a) What is the velocity of the water in the hose ?
this is no prob
A1V1 = A2V2
8.61m/s OK


b) What is the pressure differential between the water in the hose and water in the nozzle ?
i am stuck on this one.




Homework Equations





The Attempt at a Solution



heres what I am doing...
use bernoulli..

P2-P1 = (1/2pv^2)1 - (1/2pv^2)2

P2 - P1 = 634.934Pa
this is wrong.

please help ! thanks
 
Physics news on Phys.org
Did you multiply by rho?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
4
Views
2K
Replies
7
Views
938
Replies
3
Views
3K
Replies
13
Views
19K
Replies
5
Views
3K
Replies
2
Views
2K
Back
Top