Solving Buoyancy Problem: Ball Emerges from Water Surface

  • Thread starter Thread starter Hitman6267
  • Start date Start date
  • Tags Tags
    Buoyancy
AI Thread Summary
A small ball is released from a depth of 0.610 m in water, with a density 0.290 that of water, and the drag force is negligible. The initial approach using mg = mf * g was ineffective due to a mistake in density cancellation. Applying Newton's second law and kinematics led to a successful resolution of the problem. The discussion emphasizes the importance of correctly applying physical laws to solve buoyancy-related questions. Ultimately, the correct method provided the solution to how high the ball would shoot above the water surface.
Hitman6267
Messages
17
Reaction score
0
Question
Suppose that you release a small ball from rest at a depth of 0.610 m below the surface in a pool of water. If the density of the ball is 0.290 that of water and if the drag force on the ball from the water is negligible, how high above the water surface will the ball shoot as it emerges from the water? (Neglect any transfer of energy to the splashing and waves produced by the emerging ball.)

My attempt
I tried mg = m_{f} * g

but it didn't get me anywhere

Any ideas ?
 
Physics news on Phys.org
Why don't you apply Newton's second law on it? Then a little kinematics will help.
 
It worked thank you :)

I tried it, but a mistake kept the density from cancelling out. I retried it after your suggestion and it worked.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Ping-Pong Ball Submerged in Water and then Released
Replies
12
Views
8K
Will the displacement of a solid ball affect the water level?
Replies
7
Views
2K
How High Will a Lighter-Than-Water Ball Shoot Above the Surface?
Replies
2
Views
5K
What Happens to the Buoyant Force on a Beach Ball When Submerged?
Replies
4
Views
4K
What Does an Electronic Balance Measure in Water Experiments?
Replies
12
Views
2K
Calculate the max speed at which a submarine rises/dives
Replies
5
Views
2K
What is the velocity of the ball after H height? Considering wind resistance?
Replies
1
Views
2K
Solving for the Depth of Release: Pressure on a Ball
Replies
9
Views
3K
Buoyancy Problem Involving Archimede's Principle
Replies
7
Views
6K
How High Will the Ball Shoot Above the Water?
Replies
1
Views
3K

Hot Threads

Recent Insights

Back
Top