Solving Circular Motion Problems: Displacement, Speed, & Acceleration

Click For Summary
SUMMARY

This discussion addresses the nuances of solving circular motion problems, specifically focusing on displacement, speed, and acceleration. The participant successfully calculated displacement vectors, speed, and acceleration but questioned the discrepancy between two acceleration values derived from different methods. The difference arises from the approximation of the circular path using a finite number of points, which affects the accuracy of the calculated acceleration. The discussion concludes that increasing the number of points in the approximation leads to results that converge to the theoretical values.

PREREQUISITES
  • Understanding of vector components in physics
  • Knowledge of circular motion principles
  • Familiarity with acceleration calculations, including a = ΔV/Δt
  • Basic grasp of integral calculus for approximating circular paths
NEXT STEPS
  • Explore vector addition techniques in physics
  • Study the principles of circular motion and centripetal acceleration
  • Learn about the impact of approximation methods in physics problems
  • Investigate integral calculus applications in motion analysis
USEFUL FOR

Students studying physics, educators teaching circular motion concepts, and anyone interested in the mathematical modeling of motion dynamics.

snagglepuffin
Messages
4
Reaction score
0

Homework Statement



I do not know if this is the correct forum to post this in but here goes. I got all of the answers correct, but I just have a question on part F.

attachment.php?attachmentid=51207&stc=1&d=1348623932.jpg

1.) The figure shows a motion diagram
of a particle in circular motion at a
constant speed. The axes have units
of meters. Each dot represents a 5
second time interval.

a) Write out the displacement
vector from point 1 to point 2 in
component form

b) Write out the displacement vector from point 1 to point 2 as a magnitude and
angle from horizontal.

c) What is the speed of the particle? To do this, determine a velocity vector and
take its magnitude.

d) Use graphical vector addition to show the direction of the acceleration at points 1
and 3. You can do this right on the figure or on another sheet of paper.

e) From your answer in part d, find the magnitude of the acceleration at point 3.
Remember a = ΔV/Δt

f) Compare your answer from part e to the result from aradial = v2tan/r



The Attempt at a Solution


Just to show you that I actually did the work, here are the answers I got.

A) -7i+3j

B) 7.61m at 23.2° above the -x axis.

C) 1.52 m/s

D) I drew the acceleration vector on my paper.

E) 0.226 m/s/s

F) 0.231 m/s/s

My question to you is why are the answers for Part E and Part F different? They are both correct (as calculated in the problems) and both describe the magnitude of the same acceleration vector.

Any and all help would be appreciated!
 

Attachments

  • circularmotion.jpg
    circularmotion.jpg
    23.9 KB · Views: 556
Physics news on Phys.org


The difference comes from the fact that the 8 points are just an apporximation of a circle.

Try doing the same exercise with all the odd-numbered points removed(a worse appoximation of a circle), and then with twice as many as points as in the problem(a better approximation).
In the fromer case, you'll find out that the acceleration diverges even more, in the latter that it's closer to what you get from the equation in f.
Once you include infinite number of points to form the actual circle, your results will converge(integral calculus deals with this kind of infinite addition problems).

Think of what is the difference between the displacement you've been calculating, and the actual distance the point traveling in circular motion needs to cover. How does the difference affect velocity and acceleration?
 


Thank you Bandersnatch! That is what I was thinking. I re-evaluated it with more points and it was more accurate.
 

Similar threads

Replies
55
Views
3K
Replies
1
Views
820
  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
8
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K