Solving Connected Particles Homework Problem

  • Thread starter Thread starter Bucky
  • Start date Start date
  • Tags Tags
    Particles
AI Thread Summary
The problem involves two equal mass bodies, A and B, connected by a string, with A projected at a 45-degree angle. The user attempts to calculate the impulsive tension in the string when taut, using momentum equations in both the direction of AB and perpendicular to it. They express concerns about potential errors in their calculations, particularly regarding the algebra and the loss of a mass variable. A suggestion is made to express cos 45 as sqrt(2)/2 to simplify the calculations. The overall goal is to determine the correct impulsive tension, which the user believes should be 1/4 m U sqrt(2).
Bucky
Messages
79
Reaction score
0

Homework Statement


Two bodies A and B of equal mass m, connected by a light inextensible string, are placed on a smooth horizontal table with the string just taut. A is projected with velocity U at 45 degrees to the direction AB. Determine the impuslive tension in the string when it becomes taut.

Homework Equations





The Attempt at a Solution


Well, following from previous examples i tried to find the momentum in direction AB and perpendicular to AB.

Momentum in direction AB

mu + mu = U cos45
2mu = Ucos45
u = (Ucos45) / 2m

Momentum perpendicular to AB
mv = U sin45
v = (Usin45)/m

Impulsive Energy at A
T = mu
= (Ucos45)/2
= (U * 1/root2)/2


I think I've gotten it wrong. answer should be 1/4 m U root 2. can anyone help me out? I don't know if it's an algebra problem or (most likley) a method problem.
 
Physics news on Phys.org
try expressing the cos 45 as sqrt(2)/2, subbing that= u*sqrt(2)/4
 
annoyingly I've lost an 'm' somewhere, but otherwise the answer checks out :)

i didn't know cos 45 could be expressed as root(2)/2 ? or have you done some mathmatical jiggery-pokery that i have missed?
 
no real trickery, just dividing or multiplying both top and bottom by sqrt(2).
 
Last edited:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top