Solving Cylinder Volume from Rectangle Perimeter of 40cm

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A rectangle with a perimeter of 40cm, when rotated around one of its sides, forms a right cylinder. The initial calculations for the cylinder's volume were incorrect due to a mistake in squaring the radius. The correct maximum volume for the cylinder is approximately 3723.37cm³. There was a discussion about whether the perimeter equation should consider the diameter instead of just the radius, but it was clarified that the rotation occurs around one side of the rectangle, making the radius appropriate. Understanding the rotation's impact on the dimensions resolved the confusion regarding the calculations.
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Question: A rectangle with a perimeter of 40cm is rotated around one of its sides, creating a right cylinder. What is the largest possible volume for this cylinder?
Here's what I have done so far:
Equation #1:
40 = 2h + 2r
r = 20 - h
Equation #2:
Volume = pi*r^2h
= pi(20-h)(h)
= 20pi*h - h^2*(pi)
Derivate of volume: 20pi-2pi*h
10=h
Therefore, r also equals 10.
Thus, the maximum volume is 3141.592cm^3, which is incorrect.
The actual answer is 3723.37cm^3. Any help would be great. :biggrin:

Sorry, but I think this should be in the "Calculus and Beyond" board.
I'm not too sure how to move it there, though.
 
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danizh said:
Equation #2:
Volume = pi*r^2h
= pi(20-h)(h)
= 20pi*h - h^2*(pi)
I think you forgot to square the radius (20-h) when putting it in...

I may be wrong, I just looked at it quickly and that's what I saw.

EDIT: My way, my calculator now tells me 3723.3691 so yup, that was your mistake
 
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Thanks for the help, I really appreciate it.
I'll be more careful next time. :smile:
 
I have another question, wouldn't it be more appropriate if the "restraint equation" was 40 = 2h + 4r rather than 40 = 2h + 2r. It just seems to make more sense since if the cylinder is transformed into a rectangle, each side of the triangle would be a diameter (or two times the radius) rather than just the radius, which we are assuming right now. I'm just curious to know why I get the wrong answer if I do it the way that seems to be more logical to me.
 
danizh said:
I have another question, wouldn't it be more appropriate if the "restraint equation" was 40 = 2h + 4r rather than 40 = 2h + 2r. It just seems to make more sense since if the cylinder is transformed into a rectangle, each side of the triangle[\b] would be a diameter (or two times the radius) rather than just the radius, which we are assuming right now. I'm just curious to know why I get the wrong answer if I do it the way that seems to be more logical to me.


I assume you meant "rectangle" where you wrote "triangle" above. The reason a side of the rectangle is a radius not a diameter is that the rectangle is rotated about one side, not about a center line of the rectangle.
 
Ah, I understand it now! Thanks for clearing that up.
I think the key to the question is that it is rotated to create a right cylinder.
 
what did you get for your "r" value? I'm doing somethign wrong...
 
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