Solving Difficult Equations: y = -2x - 2/7 + ce^(-7x)

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Homework Statement





Homework Equations



i have done till the 2nd final step
how is it possible to get the final answer y = -2x - 2/7 + ce^(-7x)
why is it ce^(-7x) and not c/e^(-7x)?

The Attempt at a Solution

 

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I agree with you. It should be ##c/e^{-7x}=ce^{7x}##.
 
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kyu said:

Homework Statement





Homework Equations



i have done till the 2nd final step
how is it possible to get the final answer y = -2x - 2/7 + ce^(-7x)
why is it ce^(-7x) and not c/e^(-7x)?

The Attempt at a Solution


You are correct.
 
While this was a quite blatant error where the last two lines were not compatible with each other. If you are in doubt, you can always insert the solution into the differential equation and check that it actually solves it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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