Limits...what am I doing wrong ? (Without hopital)

  • #1
AlexandraMarie112
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Homework Statement



Limx--->positive infinity sqrt(3x^5-2x) - sqrt(3x^5-7x)

Homework Equations




The Attempt at a Solution


The first thing I did was rationalize. I got (5x)/ [ sqrt(3x^5-2x) + sqrt(3x^5-7x)]. Then I divided the top and bottom by x^5 but this is where I feel like I am doing something wrong. But I don't know what. Am I even supposed to divide by x^5 ? Because the other problems I've solved so far have been with an x^2.
 

Answers and Replies

  • #2
36,879
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Homework Statement



Limx--->positive infinity sqrt(3x^5-2x) - sqrt(3x^5-7x)

Homework Equations




The Attempt at a Solution


The first thing I did was rationalize. I got (5x)/ [ sqrt(3x^5-2x) + sqrt(3x^5-7x)]. Then I divided the top and bottom by x^5 but this is where I feel like I am doing something wrong. But I don't know what. Am I even supposed to divide by x^5 ? Because the other problems I've solved so far have been with an x^2.
Factor x5 out of each radical, and bring each out of its radical as x5/2.
 
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  • #3
fresh_42
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What happens, if you simply divide by / cancel x?
 

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