Solving Dynamics Homework: Frictionless Ramp & 5.0kg Block

  • Thread starter Thread starter StarMetroid
  • Start date Start date
  • Tags Tags
    Dynamics
AI Thread Summary
The problem involves a flat-bed truck with a frictionless ramp and a 5.0kg block that remains stationary relative to the ramp while the truck accelerates. The truck's acceleration causes the block to experience a downward acceleration of 9.8 m/s² and a horizontal acceleration of 13.98 m/s², resulting in a total acceleration of 17.1 m/s². The force of friction acting on the truck, calculated using the coefficient of friction (0.10), is 11,760 Newtons. The discussion seeks assistance in determining the force exerted by the truck's engine. The calculations highlight the relationship between the truck's acceleration and the forces acting on both the truck and the block.
StarMetroid
Messages
3
Reaction score
0

Homework Statement


A flat-bed truck with a frictionless ramp accelerates forward.


/l (That 35 is the angle, and a 5kg block rests on the hypotenuse)
--- / l
- - /35 l
- ---------------
-----------------
-o-----------0--

The acceleration of the truck is suck that a 5.0kg block is stationary (relative to the ramp). If the rolling coefficient of friction is (mew=0.10) Find the force the engine is exerting on the 12000kg truck.


Homework Equations


F=ma, Ffriction=Fnormal*mew


The Attempt at a Solution


I found the block accelerates 9.8m/s^2 downwards and 13.98m/s^2 to the left, ant the total acceration is 17.1m/s^2
 
Physics news on Phys.org
I found the force of friction on the truck (12000*9.8*0.1) to be 11760Netwons.
 
Please help me :'(
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top