Solving Electrostatics Problems: Contact of Neutral & Charged Spheres

  • Thread starter Thread starter apnut821
  • Start date Start date
  • Tags Tags
    Electrostatics
AI Thread Summary
The problem involves two insulated metal spheres, one neutral (X) and one charged (+1.80 E -16 C, Y). Before contact, the total charge of the system is 0 C. After the spheres are brought into contact and then separated, the total charge remains +1.80 E -16 C. Sphere X retains a charge of 0 C, while sphere Y maintains a charge of +1.80 E -16 C after separation. Understanding these charge interactions is crucial for solving similar electrostatics problems.
apnut821
Messages
3
Reaction score
0
Hi, i have been assigned a series of problems that basically follow the same pattern, but I am unable to solve the first one which is making it difficult to solve the others.

here it is

An insulated metal sphere (X), that has no net charge (neutral), is brought into contact with a similar sphere (Y) that has a charge of +1.80 E -16 C. The two spheres are the separated. a) What is the total charge of the system before and after separation? b) What are the charges of spheres X and Y after seperation?

thanks
 
Physics news on Phys.org
!a) Before separation, the total charge of the system is 0 C. After separation, the total charge of the system is +1.80 E -16 C. b) After separation, sphere X has a charge of 0 C and sphere Y has a charge of +1.80 E -16 C.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top