Solving Elevator Problem: Physics Student in Accelerating Elevator

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In the discussion about a physics problem involving a student in an accelerating elevator, the initial weight of the student is given as 564 N when the elevator is stationary. When the elevator accelerates downward at 1.97 m/s², the scale reading changes due to the net force acting on the student. Participants suggest using Newton's second law and recommend drawing a diagram to visualize the forces involved. The key is to combine the force required for downward acceleration with the student's weight to find the new scale reading. Understanding the relationship between weight, acceleration, and net force is crucial for solving the problem correctly.
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Homework Statement


A physics student stands on a bathroom scale in an elevator which is not moving. The scale reads 564 N. The elevator then accelerates downward at 1.97 m/s2. What does the scale read during this acceleration?



Homework Equations



F=ma, W=mg

The Attempt at a Solution



I thought at first the answer should be 0 N, but that is wrong...then I tried using Newton's 2nd Law F = 564 N, a = 1.97, but when I plugged this in it was stilled wrong...what equation should I use?
 
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You are using the correct formulae, but are not looking at the whole situation. First, draw yourself a diagram; then consider what force would be required to make the student accelerate downwards at 1.97m/s^2. Finally, you need to figure out how you combine this force with the weight of the student.
 
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