- #1
JBD2
- 61
- 0
Homework Statement
Solve the following:
Question 1:
[tex]\sqrt[5]{256}\div\sqrt[6]{64}=2^{x}[/tex]
Question 2:
[tex]\frac{(9^{2x-1})^{3}(3^{3x})^{2}}{(27^{x+2})^{4}}=81^{3}[/tex]
Homework Equations
None that I am aware of.
The Attempt at a Solution
Question 1:
[tex]\sqrt[5]{2^{8}}\div2^{1}=2^{x}[/tex]
Question 2:
[tex]\frac{(3^{4x-2})^{3}(3^{6x})}{(3^{3x+6})^{4}}=3^{12}[/tex]
[tex]3^{12x-6+6x-(12x+24)}=3^{12}[/tex]
[tex]6x=39[/tex]
[tex]x=6.5[/tex]
Sorry that the attempt for question 1 was lacking so much, I was just unsure of what to do with the square roots etc...As for number 2, the answer I got is incorrect, when it says that the answer in the back of my textbook is 7.
Answer Key:
Question 1:
[tex]\frac{3}{5}[/tex]
Question 2:
7
Thanks to everyone who helps.