- #1
rugapark
- 22
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I'm trying to solve this firrst order diff. equation, where I'm given the initial value, x(0)=2[tex]\frac{dx}{dt}=\frac{3x+4}{\sqrt{t}}[/tex]
[tex]\frac{dx}{3x+4}=\frac{1}{\sqrt{t}}dt[/tex]
[tex]\int\frac{1}{3x+4}dx=\int\frac{1}{\sqrt{t}}dt[/tex]
[tex]ln(3x+4)=ln(t^{\frac{1}{2}})[/tex]
this is as far as I got, do I sub in x(0)=2 into the LHS? if not, could i have some pointers to help carry on?
cheers.
[tex]\frac{dx}{3x+4}=\frac{1}{\sqrt{t}}dt[/tex]
[tex]\int\frac{1}{3x+4}dx=\int\frac{1}{\sqrt{t}}dt[/tex]
[tex]ln(3x+4)=ln(t^{\frac{1}{2}})[/tex]
this is as far as I got, do I sub in x(0)=2 into the LHS? if not, could i have some pointers to help carry on?
cheers.
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