Solving for A and B in a piecewise function

odmart01
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Homework Statement


ax+b, x>-1
f(x)= bx^2-3, x less than equal to: -1

Homework Equations


the limits on both sides


The Attempt at a Solution


found the limit on both sides of the equation but don't know what to do next.
 
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odmart01 said:

Homework Statement


ax+b, x>-1
f(x)= bx^2-3, x less than equal to: -1

Homework Equations


the limits on both sides


The Attempt at a Solution


found the limit on both sides of the equation but don't know what to do next.
I don't think you provided all of the information in this problem. For example, aren't you supposed to find values for a and b so that f is continuous at x = -1?
 
Mark44 said:
I don't think you provided all of the information in this problem. For example, aren't you supposed to find values for a and b so that f is continuous at x = -1?

yes, that's right
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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