Solving for Object Collisions and Velocity with Displacement Formula

  • Thread starter Thread starter Chatito
  • Start date Start date
  • Tags Tags
    Physics Test
AI Thread Summary
Two objects are moving towards each other, with Object 1 starting at 25 m and moving at -5.5 m/s, while Object 2 starts at 13 m and moves toward Object 1. They collide after 0.65 seconds, and the goal is to determine the collision point and the velocity of Object 2. The displacement formula is mentioned, but initial calculations provided are incorrect. To solve the problem, one must calculate the distance each object travels in 0.65 seconds to find their collision point. Understanding their displacements will clarify where and how they collide.
Chatito
Messages
2
Reaction score
0
1. Object 1 starts at 25 m and moves with a velocity of –5.5 m/s . Object 2 starts at 13 m and moves directly toward object 1. The two objects collide 0.65 s after starting. I need to find when they both collide and the velocity of Object 2

2. I don't know much but I know the displacement formula is deltax=x_f - x_i3. I did 25/13=1.92 and -5.5/0.65=-8.46. I know this is wrong but this is my work and I hope to find an answer
 
Physics news on Phys.org
Chatito said:
1. Object 1 starts at 25 m and moves with a velocity of –5.5 m/s . Object 2 starts at 13 m and moves directly toward object 1. The two objects collide 0.65 s after starting. I need to find when they both collide and the velocity of Object 2

2. I don't know much but I know the displacement formula is deltax=x_f - x_i3. I did 25/13=1.92 and -5.5/0.65=-8.46. I know this is wrong but this is my work and I hope to find an answer
You have two objects, both moving at constant velocities.
Write an expression for the distance Object 1 covers.
Write an expression for the distance Object 2 covers.
What is the total distance the two objects cover?
At what point does Object 1 collide with Object 2?
 
Is this a 1D problem? Object 1 is moving downward and Object 2 is moving upward (no gravity?), right?
The -5.5 / 0.65 = -8.46m gives you how far Object 1 moved in the time. So by deductive reasoning, you should know how far Object 2 traveled in the same .65 seconds.
 
Chatito said:
1. Object 1 starts at 25 m and moves with a velocity of –5.5 m/s . Object 2 starts at 13 m and moves directly toward object 1. The two objects collide 0.65 s after starting. I need to find when they both collide and the velocity of Object 2

2. I don't know much but I know the displacement formula is deltax=x_f - x_i3. I did 25/13=1.92 and -5.5/0.65=-8.46. I know this is wrong but this is my work and I hope to find an answer
you already mention that they collide 0.65s after starting...you again ask when they both collide...I think the question...where they collide...how far they will collide from the starting point. If the question is that,,,,,,,,,you need to find out their displacement in .65s
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top