Solving for Object's Distance with 6N & 4s

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To determine how far a 1 kg object travels under a force of 6 Newtons for 4 seconds, one must apply Newton's 2nd law, which states that acceleration equals force divided by mass, resulting in an acceleration of 6 m/s². During the 4 seconds, the object accelerates uniformly, and the distance traveled can be calculated using the formula for distance under constant acceleration, yielding a total distance of 48 meters. After the force is removed, Newton's 1st law indicates that the object will continue to move at the final velocity it reached at the end of the 4 seconds, which is 24 m/s. Therefore, the object will maintain this velocity indefinitely in the absence of friction or other forces. Understanding these principles is crucial for solving problems related to motion and forces in classical mechanics.
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mentor note: moved from classical physics hence no HH template.

I am sure this will not take someone long to figure out. It has been awhile and while I do remember some of my basic physics I can't remember how to tie it all together. So her it is: How far would a 1 kg object travel with 6 Newtons of force applied for 4 seconds (assume friction is 0)?
 
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What is the acceleration of the object?
 
Your question can be answered if you have understand Newton's 1st and 2nd law of classical mechanics.
What does Newton's 2nd law tell us for the acceleration of the object during the 4seconds that the force is applied on it?
What does the same law tell us for the acceleration after the duration of 4 seconds, when there is no force applied to the object. What does Newton's 1st law tell us for the motion of the object after the duration of 4 seconds?
 
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