Solving for Slowest Speed of a Ball: 2.25m Radius

AI Thread Summary
To determine the slowest speed of a ball with a radius of 2.25 m at the bottom of its path, one must first draw a free body diagram and apply Newton's second law. The problem involves calculating the speed necessary for the ball to complete a circular motion at the top of the path, where gravity plays a crucial role. The equation derived is v^2 = g * r, where g is the acceleration due to gravity. After calculating v^2, the final step is to take the square root to find the actual speed. This approach clarifies the dynamics involved in circular motion.
liz777
Messages
19
Reaction score
0

Homework Statement


A ball has a radius of 2.25 m. What is the slowest speed of the ball at the bottom which will just make it around at the top of the path?

The Attempt at a Solution



I don't even know where to start with this problem. I don't understand it. Any help would be greatly appreciated!
 
Physics news on Phys.org
liz777 said:
I don't even know where to start with this problem. I don't understand it.

Neither do I, because you didn't type in the entire problem statement. I'm guessing that the ball is tethered to a rope of radius 2.25 m, but that's just a guess. Please type in the problem statement exactly as it appears on your assignment.
 
oh sorry...here it is:

When one spins a ball in a circular path which has a radius of 2.25 m, what is the slowest speed of the ball at the bottom which will just make it around at the top of the path?
 
You should begin by drawing a free body diagram of the ball at the top of its path. Then write down Newton's second law for the ball at that point. That's how you start all dynamics problems at this level.
 
ok, I drew a diagram and I think I understand. Gravity pulls down on the ball, which is the acceleration so:
v^2=gr
=(9.8)(2.25)

Is this correct?
 
Right, just remember to take the square root. You found v^2, not v.
 
ok, thank you! :) I understand it.
 
Back
Top