Solving for Speed: Chip Dipped in Dip w/ Radius .5m

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The discussion revolves around calculating the speed of a chip dipped in a circular dip with a radius of 0.5 meters, where a flavor crystal experiences twice the normal gravity. The initial attempt to find the speed by simply doubling the acceleration due to gravity (9.8 m/s²) to get 19.6 m/s is questioned, as it conflates force with velocity. Clarification is sought on whether the problem involves calculating velocity after accelerating from rest over a distance of 0.5 m under constant acceleration. The centripetal force equation is mentioned, but confusion remains regarding the mass of the chip and its relevance to determining speed. The conversation highlights the need for a clearer understanding of the physics involved in the problem.
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Homework Statement


a chip is dipped into dip and bottoms out in a circle with radius r. A flavor crystal on the chip is put under twice the normal gravity. If r = .5m, how fast is the chip traveling at the bottom of the dip. Neglect the mass of the chip.


Homework Equations





The Attempt at a Solution



My answer is taking 9.8 *2 which is 19.6 m/s. Is this correct? It seems to easy. But don't we need to take into account the mass of the chip?
 
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bigdaddy said:

Homework Statement


a chip is dipped into dip and bottoms out in a circle with radius r. A flavor crystal on the chip is put under twice the normal gravity. If r = .5m, how fast is the chip traveling at the bottom of the dip. Neglect the mass of the chip.


Homework Equations





The Attempt at a Solution



My answer is taking 9.8 *2 which is 19.6 m/s. Is this correct? It seems to easy. But don't we need to take into account the mass of the chip?
The acceleration due to gravity is 9.8 m/s2, not m/s and is not a velocity. In any case, "is put under twice the normal gravity" refers to a force not acceleration.

I frankly don't understand the problem- unless it is a very awkward way of asking what velocity something will have after starting from 0 velocity and moving 0.5 m at acceleration 19.6 m/s2. If that is the case, you need equations for velocity and distance with constant acceleration. How long will it take to go .5 m with constant 19.6 m/s2 acceleration? How will the velocity have changed in that time?

(Chip and dip? And the bowl of dip has a 50 cm radius? How big is the bottle of beer?)
 
I didnt understand the problem myself. I asked the guy who made the problem up (another student) and he explained what he was asking. now i understand. He meant to say basically it is a fluid motion from bag down through dip and up to mouth. the dipping motion has the .5m radius. He was saying Fc=mv^2/r ==> Fc=mg ==> netforce = 2mg-mg=mg. Only thing i don't understand now is what is the mass? Do i make something up? Another thing is that just tells me the centriputal force on the chip it doesn't really tell me how fast it is going.

Not just how big the beer is but what kind? also, i just figured out on this post how to get the ^ in. Dont think i have ever seen that on the keyboard. I know its 9.8m/s^2 i just didnt see that neat little symbol above the 6. haha
 
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