Solving for Tension in an Elevator with Acceleration of 3.0 m/s^2 | Physics Help

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To solve for the tension in the cable of an elevator weighing 25,000 N accelerating upward at 3.0 m/s², first calculate the mass of the elevator using the formula m = weight/g, which gives m = 25,000 N / 9.8 m/s². The net force acting on the elevator is the sum of the gravitational force and the tension in the cable, expressed as Net Force = Gravity + Tension. Using Newton's second law, the net force can also be calculated as Net Force = m * a, where a is the acceleration. By equating the two expressions for net force, one can solve for the tension in the cable, ensuring it is greater than the gravitational force acting downward. Understanding these relationships is crucial for solving the problem correctly.
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guys iam takin physics
its a takhom test
nd i don't get physics attt allll!
pllz hlp me with this
i need to show work as well

an elvtor weighing 25,000 N is supported by a steal cable. that is the tension in the cable wehn the elavotor is begin accelerated upward at the reate of 3.0 m/s^2? (g= 9.8m/s^2)
pleasezz help[
 
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TIP: The tension in the cable must be greater than the gravity pulling down. Think about that.

Also remember that if this is an isolated system where only tension and gravity are acting on the elevator, the net force is equal to the gravity + tension. Is there a way you can find the mass? Once you find the mass, might there be also be a way to calculate the netforce using mass and the acceleration? REmember, Netforce=Gravity+Tension
 
remember

\sum \overline{F} = m\overline{a}

directions are imp.
 

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