Solving for Vo: Graph Analysis of Vs vs t

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The discussion focuses on graphing the output voltage (Vo) using the equation Vs=Vi(1-e^-t/T). The user is uncertain about how to graph Vo due to limited information and contemplates whether to calculate output voltage at specified time increments. It is confirmed that using Vo=1 Volt and calculating voltages from t=-0.1s to t=0.5s is appropriate. Additionally, the importance of matching the tick marks on the graph to the original picture is emphasized. The conversation highlights the need for clarity in selecting time intervals for accurate graph representation.
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Homework Statement


Screen Shot 2016-02-15 at 8.02.45 PM.png


Homework Equations


Vs=Vi(1-e^-t/T)

The Attempt at a Solution


I am stuck on B. I am not sure how I am supposed to graph Vo with so little information. Do i just use V=Vo(1-e^-t/T) and find the output voltage for each time increment that is on the original graph. So Vo=1Volt and we have T and we just find voltages from t=-.1s to t=.5s? And then we graph voltage out vs time?
 
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That's right - but why stick to the time intervals shown on the graph, why not choose much smaller intervals?
You may be expected to make sure the tick-marks on the graph match the picture.
 
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