Solving Friction Force and Acceleration Problems

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SUMMARY

This discussion addresses the physics of friction force and acceleration involving a block on a horizontal table. The coefficients of static friction (μ_s) and kinetic friction (μ_k) are critical in determining the forces acting on the block. When a force less than the threshold force is applied, the frictional force equals half of that applied force, while the acceleration after the block starts moving is determined by the net force, which is the applied force minus the kinetic friction force (μ_k * m * g). The acceleration can be expressed as a = (f - μ_k * m * g) / m.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static and kinetic friction coefficients
  • Familiarity with basic algebra for solving equations
  • Concept of normal force in physics
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  • Study the principles of Newton's second law of motion
  • Learn about the differences between static and kinetic friction
  • Explore the concept of normal force and its calculation
  • Investigate real-world applications of friction in mechanics
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of friction and acceleration problems.

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Homework Statement



A block of mass m lies on a horizontal table. The coefficient of static friction between the block and the table is mu_s. The coefficient of kinetic friction is mu_k. (mu_k<mu_s)
a: Suppose you push horizontally with half the force needed to just make the block move. What is the magnitude of the friction force?
b: Suppose you push horizontally with precisely enough force to make the block start to move, and you continue to apply the same amount of force even after it starts moving. Find the acceleration a of the block after it begins to move? {Express your answer in terms of some or all of the variables mu_s, mu_k, and m, as well as the acceleration due to gravity g}


Homework Equations


F_k = mu_k.N (N is normal force)
F_s = mu_s.N


The Attempt at a Solution


I was wondering a: 1/2.mu_k.m.g
b: mu_k.g
could anybody please expalin this problem?

Thanks in advance
 
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With in the limit, the frictional force is a self adjusting force.
So in a: frictional force is f/2, because the block is not moving.
In b: Net force acting on the block is f - μk*mg. Now find the acceleration.
 

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