Solving Functions: Find f+g=5 | [0,inf)

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To solve for functions f and g such that (f+g)(x) = 5 with the domain [0, inf), it is confirmed that (f+g)(x) means f(x) + g(x). Simple solutions include f(x) = 4 and g(x) = 1, or f(x) = 3 and g(x) = 2. More complex examples involve using f(x) = √x and g(x) = 5 - √x, or defining g(x) as 5 - f(x) for any valid f(x) within the specified domain. The discussion emphasizes the flexibility in choosing functions as long as they satisfy the equation and domain requirements. Various function combinations can be explored to meet the criteria.
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Homework Statement


Find two functions f and g such that (f+g)(x) =5 and the domain of f+g is [0,inf)


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The Attempt at a Solution


I am wondering if (f+g)(x) means f(x)+g(x)

If so then can i just say that f(x)=4 and g(x)=1 or f(x)=3 and g(x)=2?
 
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Yes, looks right to me.
 
Thank You :!)
 
Or you could do something exciting like
f(x) = \sqrt{x}, g(x) = 5 - \sqrt{x}
or
f(x) = \sqrt{x} + x^2 - \frac{3 x^{12}}{1 + x}, g(x) = 5 - \sqrt{x} + x^2 - \frac{3 x^{12}}{1 + x}
or any other function f(x) with domain [0, \infty[ and define g(x) = 5 - f(x).
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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