Solving Fx for 50kg Skier Down Hill

  • Thread starter Thread starter 1MileCrash
  • Start date Start date
  • Tags Tags
    Hill
AI Thread Summary
In this discussion, a 50kg skier is skiing down a frictionless slope at a 16-degree angle, and the challenge is to determine the wind force component Fx when the skier's velocity is constant. The confusion arises from the concept of constant velocity despite the gravitational force acting on the skier. It is clarified that if the skier's velocity is constant, the net force acting on them must be zero, meaning Fx must balance the gravitational force component acting down the slope. The forces in the x-direction are -sin(16)*m*g and Fx, which must be equal and opposite for the skier to maintain constant velocity. The discussion highlights the importance of understanding force balance in scenarios involving constant velocity motion.
1MileCrash
Messages
1,338
Reaction score
41

Homework Statement



A 50kg skier skis directly down a frictionless slope angled 16* to the horizontal. Assume the skier moves at a negative x direction. A wind force with component Fx acts on the skier.

What is Fx if the skier's velocity magnitude is constant?

Homework Equations





The Attempt at a Solution



I really have no idea. I assume Fx is equal to the force the skier exerts "on the air" so F = ma on the skier.

But I am utterly confused when they say velocity is constant. He is going down the slope due to gravity, how could his velocity be constant? It makes no sense to me.
 
Physics news on Phys.org
The negative x direction is the direction the skier goes. There are two forces which act in the x direction on the skier, -sin(16)*m*g and F_x, they are equal and opposite.
 
How would I adjust that if the skier's velocity is increasing 10m/s/s?

-sin(16)(5)(9.8 + 10t)
?
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »

Similar threads

Using Momentum, KE and PE to solve this skier velocity problem
Replies
13
Views
2K
How to calculate the kinematics of an object pushed up an inclinex plane?
Replies
7
Views
1K
What Are the Gravitational and Normal Forces on a Skier on a Slope?
Replies
4
Views
2K
Terminal velocity of a skier using a Momentum Balance
Replies
1
Views
2K
Solving Physics Problem: 31kg Skier on 13° Slope w/ Wind Force
Replies
5
Views
3K
Forces and Free-Body Diagrams in Real-World Scenarios
Replies
5
Views
4K
Force and Motion: Skier's Fx for V Constant, Increasing 1.5 m/s2, 3.0 m/s
Replies
9
Views
2K
How Do You Calculate Skier's Mass and Acceleration with Newton's Second Law?
Replies
2
Views
1K
Speed skier travelling up a hill
Replies
7
Views
3K
How Do Frictional Forces Affect a Skier's Acceleration?
Replies
4
Views
2K

Hot Threads

Recent Insights

Back
Top