Solving gradients of right angle triangle

  • Thread starter Thread starter mamort
  • Start date Start date
  • Tags Tags
    Angle Triangle
mamort
Messages
6
Reaction score
0
Please take a look at attached diagram displaying gradients of each line, please explain how m3 is obtained.
Gradient Problem.jpg
 
Mathematics news on Phys.org
No. If you don't specify how long the arms of the short sides of the right triangle need to be, then you can make m3 be whatever you want, and you'll still have a right-triangle with 1/x and -x as the gradient of two of the sides.
 
True I think I might of head down the wrong path I am trying to solve the following problem in the diagram below. I am unsure how u1 is obtained. I assume that the gradient of the green line is used to solve as shown below

m3 = (hz+delta_hz)/(u1)
therefore
u1 = (hz+delta_hz)/m3
where
m3 = 1/k3+k3

If this is the case then how has m3 = 1/k3 + k3 been calculated?
Otherwise can you please explain how u1 has been obtained?
Geometric Problem.jpg
 

Thread 'What Exactly is Dirac’s Delta Function? - Insight'

Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
View full post »

Thread 'Fermat's Last Theorem'

Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
View full post »
Thread 'Imaginary Pythagorus'

Thread 'Imaginary Pythagorus'

I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
View full post »

Similar threads

MHB Difference of angles in a triangle
Replies
4
Views
1K
MHB Acute angle of right triangles
Replies
4
Views
1K
B More similar triangle problems
Replies
16
Views
513
I Math Myth: The sum of all angles in a triangle is 180°
Replies
1
Views
1K
I What is the name of this geometry theorem?
Replies
4
Views
2K
I Geometry problem of interest with a 3-4-5 triangle
2
Replies
59
Views
2K
B Understanding the Pythagorean Theorem
Replies
38
Views
4K
I Find Angles in Right Angle Triangles
Replies
4
Views
1K
B Why does the trigonometry of obtuse angles use ref angles?
Replies
10
Views
2K
I Help with area formula using direction cosines
Replies
3
Views
2K

Hot Threads

Recent Insights

Back
Top