Solving Gravitational Force: F_g between Ring & Mass m at Distance x

AI Thread Summary
The discussion focuses on calculating the gravitational force F_g between a ring and a mass 'm' at a distance 'x' from the ring's center. The user derived a formula for gravitational force using potential energy integration, resulting in F(d) = (2GmM)/(r²+x²)^(3/2), which differs from the provided answer. They suspect an error in their integration approach, particularly regarding the inclusion of the cosine component in the work done calculation. The correct answer given is F = (GMmx)/(r²+x²)^(3/2), highlighting the discrepancy in the user's method. The thread seeks clarification on the integration steps to reconcile the difference in results.
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Homework Statement



What is the intensity of the force F_{g} between the ring and a mass 'm', which is at a distance 'x' from the center of the ring?

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The Attempt at a Solution



I have got to my own answer, but it is different from the given one. Here's what I did:

There's a potential energy between 'm' and a dM from the ring, which is given by dU=-G*m*dM/d and d=\sqrt{r^{2}+x^{2}}.

From this, I can find the total potential energy by integrating dU from 0 to M, which gives me U=-\int^{M}_{0}\frac{G*m*dM}{d}=\frac{-G*m*M}{\sqrt{r^{2}+x^{2}}}

As the variation in the potential energy is equal to the negative of the work done, I did -\int^{0}_{d}F(d)*dd=\frac{-G*m*M}{\sqrt{r^{2}+x^{2}}}\RightarrowF(d)=\frac{2*G*m*M}{(r^{2}+x^{2})^{3/2}}

So, what's wrong? Thanks
 
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I think -\int^{0}_{d}F(d)*dd should be -\int^{0}_{d}F(d)*cos\theta*dd, but even this way I didn't get the right answer.
 
Sorry, forgot to post the given answer for the exercise: F = \frac{GMmx}{(r^2+x^2)^{3/2}}
 
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