Solving GRE Spheres: Find h0 from h

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SUMMARY

The discussion centers on solving a physics problem involving two inelastic collisions of spheres A and B, where sphere A of mass M is raised to height h0 and collides with sphere B of mass 3M. The user initially applied conservation of energy incorrectly, leading to an erroneous conclusion that h = (1/4)m. The correct approach requires using momentum conservation principles, resulting in the correct maximum height h being (1/16)h0 after the collision.

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"Two small spheres of putty, A and B, of mass M and 3M, respectively, hang from the ceiling on strings of equal length l. Sphere A is drawn aside so that it is raised to a height h0 and then released. Sphere A collides with sphere B; they stick together and swing to a maximum height h equal to "

This is an exercise I am perplexed about as to why I got the wrong answer. I used conservation of energy.

Ei = mgh0

Ef = (m+3m)gh

Ef = Ei

mgh0 = (m+3m)gh

Therefore h = (1/4)m

This answer is wrong. The correct answer is (1/16)h0. Where'd I go wrong? Thanks!
 
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They stick together after collision, that (as well as the fact that they are made of putty) should tell you that collision is inelastic and kinetic energy is not conserved. You have to consider momentum conservation to calculate Ef.
 
Thanks!
 

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