Solving Indefinite Integrals: Tips, Hints & Help

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Homework Help Overview

The discussion revolves around solving indefinite integrals, focusing on various complex integrals that the original poster is practicing for a test. The subject area includes integration techniques and strategies for handling more challenging problems.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts several integrals, expressing confusion over their approaches, particularly with substitution and integration by parts. Participants suggest rewriting expressions and breaking down integrals into simpler components.

Discussion Status

Participants are actively engaging with the original poster's attempts, offering hints and suggestions for rewriting integrals and considering different methods. There is a collaborative exploration of various approaches without a clear consensus on the best method for each integral.

Contextual Notes

The original poster indicates that these problems are for practice and not for homework, which may influence the nature of the discussion and the types of hints provided. There is also mention of specific integrals that involve odd powers and the need for substitution techniques.

rooski
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I am having much trouble with indefinite integrals - i get most of the basic theory behind them but as soon as i am confronted with a larger more complex question i get stuck too easily.

These questions are not for my homework, they are just practice for my test. Any hints, tips and general help is appreciated.Homework Statement

1. \int x^{2} / (x^{2} - 4) dx

2. \int (x + 1) ln x dx

3. \int (2 - \sqrt{x})^{2} / x dx

4. \int sec^{2} x \sqrt{1 + tan x} dx

5. \int cos^{2} x sin^{3} x dx

Attempts.

1. I started with u substitution and made u = x^2. Since du = 2x, i did \int x / ( x^{2} - 4 ) x dx is this proper?

2. Integration by parts... \int ( x + 1 ) ln x dx = ( 1/2x^{2}ln x ) + ln x^{2} - 1/4 x^{2} + x + C - is this right?

3. :confused:

4. I know that \int sec^{2} x = tan x but that's the extent of my progress.

5. :confused:

any help appreciated.

i will be posting more problems and attempts as i continue to get stumped.. :redface:
 
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For 1, I recommend rewriting the numerator as (x^2-4)+4. Then work with that.

For 2, expanding then taking care of each integral individually will help.

For 3, expansion again will save you.
 
For #1 i assume you mean for me to do that so i can make u = x^2 - 4... Right? If that is the case then i need to find a way to incorporate du/2 = x into it though... Since du = 2x.

For #2 i also cannot find where 1/x dx fits into it. I made u = ln x.

Also i have a new question... \int sin^{5} x dx - not sure what to do in the event of an odd power.
 
Last edited:
Well, for #1, by making the numerator x^2-4+4, you can rearrange your integral to this:

\int \frac{x^2-4+4}{x^2-4} dx = \int 1 + \frac{4}{x^2-4} dx

The second integral in #1, if I have it right, requires a trig substitution.

For #2, you have x ln(x) + ln(x). Make that two integrals...

\int x ln(x) dx + \int ln(x) dx

And then solve each integral individually by parts.

For your new one, change sin^2(x) = 1 - cos^2(x). Then you have \int sin^3(x) - sin^3cos^2(x) dx. Repeat to fix the sin^3 term.
 

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