Solving Inequality Problem with c1 to c2009

  • Thread starter Thread starter thebluelagoon
  • Start date Start date
  • Tags Tags
    Inequality
thebluelagoon
Messages
16
Reaction score
0

Homework Statement


Let c1, c2, c3, …, c2009 be a sequence of real numbers such that |cn – cn+1| < 1 for 1 < n <2008. Show that:
| c1+c2+…+c2009 c1+c2+…+c2008 |
|2009......2008...|< ½


Homework Equations



See above

The Attempt at a Solution



Well I simplified by cross-multiplying, getting
2008(c1 + c2 + ... + c2009) - 2009(c1 + c2 + ... + c2008)

Which thus gives us
-c1 - c2 - ... - c2008 + 2008c2009

I want to use |cn - cn+1| < 1 but I then noticed that's only for 1<n<2008 (is this a parameter that'll affect us?) and then also that bracketing gives us

-(c1+c2+...+c2008 - 2008c2009).

I just don't know the next step now. Any pointers would be appreciated!
 
Physics news on Phys.org
Um, can no-one help me? I'm sure it's not that hard, I'm just missing the next step. Sorry to bump it, but it really is bugging me.
 
You have completely left out the right side of your inequality. What will that be after "cross multiplying"?
 
2017036

so could we then change it to -c-c2-...-c2008 <2017036 - 2008c2009
and dow something with that?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Replies
11
Views
3K
Replies
4
Views
7K
Replies
2
Views
1K
Replies
7
Views
1K
Replies
4
Views
5K
Replies
13
Views
14K
Replies
3
Views
3K
Back
Top