Solving Int. with Trig Substitution for Beginners

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SUMMARY

The discussion focuses on solving the integral \(\int\frac{\sqrt{1+x}+\sqrt{1-x}}{\sqrt{1+x}-\sqrt{1-x}}{dx}\) using trigonometric substitution. Participants emphasize the importance of simplifying the expression algebraically and suggest rationalizing the denominator by multiplying both the numerator and denominator by \(\sqrt{1-x}+\sqrt{1+x}\). This method leverages the identity \((\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b})=a-b\) to facilitate the integration process.

PREREQUISITES
  • Understanding of basic calculus concepts, particularly integration.
  • Familiarity with trigonometric substitution techniques.
  • Knowledge of algebraic manipulation, including rationalizing denominators.
  • Experience with square root expressions and their properties.
NEXT STEPS
  • Study trigonometric substitution methods in calculus.
  • Practice rationalizing denominators in complex fractions.
  • Explore algebraic simplification techniques for integrals.
  • Review integration techniques involving square root functions.
USEFUL FOR

Students beginning their calculus journey, particularly those struggling with integration techniques and algebraic manipulation. This discussion is beneficial for anyone looking to improve their understanding of trigonometric substitution in calculus.

stihl29
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Homework Statement


[tex]\int\frac{\sqrt{1+x}+\sqrt{1-x}} { \sqrt{1+x}-\sqrt{1-x}}{dx}[/tex]


Homework Equations


I believe trig substitution can be used here. I'm not very good at calculus only beginning to take calc classes, and guideance would be wonderful. because i want to get better.


The Attempt at a Solution


I don't have any idea on what to substitute.
x = some thing like x^2 ??
or u = 1 - x
and u = 1 + x ??
 
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The first thing you want to do is simplify the expression algebraically. It will help to rationalize the denominator by multiplying numerator and denominator by sqrt(1-x)+sqrt(1+x). The trick here is that (sqrt(a)-sqrt(b))*(sqrt(a)+sqrt(b))=a-b. Try simplifying it and see how far you can get.
 
ohhhh, thank you, i can't attempt it at this moment but your solution looks promising !
 

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