Solving Klein Gordon’s equation

Click For Summary
The discussion focuses on a proposed solution to the Klein-Gordon equation using the separation of variables method, where the solution is expressed as a product of functions of time and space. The derived equation simplifies to a form that leads to a general solution involving exponential functions. Boundary and initial conditions are applied, resulting in specific values for the constants in the solution. A key question remains regarding the correctness of the steps taken to reach the final equation and how to determine the value of the constant k. The conversation highlights the need for clarification on the distinction between the scalar wave equation and the Klein-Gordon equation.
Safinaz
Messages
255
Reaction score
8
Homework Statement
I try to solve Klein Gordon’s equation for specific boundary and initial conditions
Relevant Equations
The Klein Gordon’s equation for a masses scalar is given by :
## \left( \frac{\partial^2}{\partial t^2} - \frac{\partial^2}{\partial x^2} \right) \phi (x, t) = 0 ##………(1)
My solution:

Let ## \phi (x, t) = F(x) A(t) ##, then Eq. (1) becomes

##
\frac{1}{A(t)} \frac{\partial^2}{\partial t^2} - \frac{1}{F(x)} \frac{\partial^2}{\partial x^2} = 0
##

So that : ## \frac{\partial^2}{\partial t^2} = k^2 ~A (t)##, and ## \frac{\partial^2}{\partial x^2} = k^2 ~F (x)##.

Leads to :
##
\phi(t,x) = ( c_1 e^{kt} + c_2 e^{-kt} ) ( c_3 e^{kx} + c_4 e^{-kx} )
##

Assuming BC and IC :

##
bc={\phi[t,0]==1,(D[\phi[t,x],x]/.x->Pi)==0}
##
##
ic={\phi[0,x]==0,(D[\phi[t,x],t]/.t->0)==1}
##

BC leads to ##c_3 = c_4= 1/2 ## and the IC leads to to ##c_1=- c_2= 1/2 ##.

Ending up by :
##
\phi(t,x) = \frac{1}{4} e^{k(t-x)} - \frac{1}{4} e^{-k(t-x)}……… (2)
##

So any help are these steps correct till Eq. (2) ? And how to determine ##k##?
 
Last edited:
Physics news on Phys.org
You just wrote down the scalar wave equation, not the Klein-Gordon equation.
 
First, I tried to show that ##f_n## converges uniformly on ##[0,2\pi]##, which is true since ##f_n \rightarrow 0## for ##n \rightarrow \infty## and ##\sigma_n=\mathrm{sup}\left| \frac{\sin\left(\frac{n^2}{n+\frac 15}x\right)}{n^{x^2-3x+3}} \right| \leq \frac{1}{|n^{x^2-3x+3}|} \leq \frac{1}{n^{\frac 34}}\rightarrow 0##. I can't use neither Leibnitz's test nor Abel's test. For Dirichlet's test I would need to show, that ##\sin\left(\frac{n^2}{n+\frac 15}x \right)## has partialy bounded sums...