Solving Laplace Transforms Homework

AI Thread Summary
The discussion centers on solving a Laplace transform problem for a linear time-invariant (LTI) system with the transfer function 1/(s^2 + 4). The user derived the corresponding differential equation, y'' + 4y = x, and sought initial conditions to ensure the output y=0 for t>=0 when a unit impulse is applied. They correctly identified the need for initial conditions but encountered discrepancies in their MATLAB results. The conversation highlights the importance of distinguishing between time functions and their Laplace transforms, specifically using y for time functions and Y for transformed variables. Clarification on the initial conditions, particularly y'(0+), is emphasized as crucial for accurate results.
zhaniko93
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Homework Statement



I'm given the transfer function of LTI system is \frac{1}{s^2 + 4}

Homework Equations



H(s) = \frac{Y(s)}{X(s)}

The Attempt at a Solution



first of all I had to find diff. equations of the system. I found that it's y'' + 4*y = x;
Then they asked to find such initial conditions that if I applied unit impulse at input, I got y=0 for time t>=0; I took Laplace transform of diff. equation with initial conditions and got that s^2Y - sY(0) - Y'(0) + 4Y = 1; I want y=0, so Y=0 and 1+sY(0) + Y'(0) = 0; I'm wrong in something...
 
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Matlab

Code:
syms y(t) x(t) a t
Dy = diff(y);
A = dsolve(diff(y, 2) + 4*y == dirac(t), y(0) == 0, Dy(0) == -1);
ezplot(A, [0 10])

pretty(laplace(A))

I get something slightly different in matlab
 
Thanks milesyoung, it helped!
 
You should use y for the time functions and Y for the transformed variables.

You are right in saying y(0+) = 0 but what about y'(0+)?
 
rude man said:
You are right in saying y(0+) = 0 but what about y'(0+)?
He/she wrote the correct initial conditions in the code segment.
 

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