Solving Linear Equations with Matrices: Help Needed

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In summary, a set of m linear equations in n unknowns can be represented by an m x n matrix A of coefficients and an m x 1 column vector h^T of right-hand sides. The number of parameters in the solution depends on the rank of the matrix A and the augmented matrix (A : h^T), which is the matrix A with h^T added as a new column. The questions to be answered for each case are: Can the situation occur? Is the set of equations consistent? How many parameters does the solution have?
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lukesta10123
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A set of m linear equations in n unknowns has the m × n matrix A of coefficients
and the m × 1 (column) vector hT of right-hand sides. (Later we shall write this as AxT=hT). T = transpose
In each of cases (a) to (d) below, answer as many as possible of the following questions.
Can the situation occur?
If so, is the set of equations consistent?
If so, how many parameters has the solution?
(a) m = 6, n = 8, r(A) = r(A : hT) = 3 .
(b) m = 7, n = r(A) = r(A : hT) = 3 .
(c) m = 4, n = 5, r(A) = 3, r(A : hT) = 4 .
(d) m = 4, n = 5, r(A) = r(A : hT) = 20 .

Any help on how to approach answering these would be of much help!

very stuck on this.
 
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lukesta10123 said:
A set of m linear equations in n unknowns has the m × n matrix A of coefficients
and the m × 1 (column) vector hT of right-hand sides. (Later we shall write this as AxT=hT). T = transpose
In each of cases (a) to (d) below, answer as many as possible of the following questions.
Can the situation occur?
If so, is the set of equations consistent?
If so, how many parameters has the solution?
(a) m = 6, n = 8, r(A) = r(A : hT) = 3 .
(b) m = 7, n = r(A) = r(A : hT) = 3 .
(c) m = 4, n = 5, r(A) = 3, r(A : hT) = 4 .
(d) m = 4, n = 5, r(A) = r(A : hT) = 20 .

Any help on how to approach answering these would be of much help!

very stuck on this.

Your notation might be confusing to some - it would be better to write hT and AxT as h^T and (Ax)^T to better get across the idea that T represents "transpose" and isn't some other matrix.

What does the notation r(A) = r(A : h^T) = 3 mean to you?
 

Related to Solving Linear Equations with Matrices: Help Needed

1. What are linear equations and matrices?

Linear equations are mathematical equations that involve only variables with a degree of 1, such as x or y. Matrices are rectangular arrays of numbers or variables that are used to represent and solve linear equations.

2. How do you solve linear equations using matrices?

To solve linear equations using matrices, you first need to set up a matrix equation by representing the coefficients and constants of the linear equation in a matrix form. Then, you can use matrix operations such as multiplication, addition, and subtraction to simplify the equation and isolate the variable you are solving for.

3. What are the benefits of using matrices to solve linear equations?

Using matrices to solve linear equations can make the process more efficient and organized, especially when dealing with systems of equations. It also allows for the use of matrix operations, which can make solving equations with multiple variables easier.

4. Can you explain the steps for solving a linear equation with matrices?

The steps for solving a linear equation with matrices include setting up a matrix equation with the coefficients and constants, using matrix operations to simplify the equation, and isolating the variable you are solving for. Finally, you can solve for the variable by performing the inverse operation on both sides of the equation.

5. Are there any limitations to solving linear equations with matrices?

Solving linear equations with matrices is limited to equations that have only variables with a degree of 1. It also requires knowledge of matrix operations and may not always be the most efficient method for solving equations with only one variable.

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