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Hi, I am having a little trouble solving a linear equation:
y' cosx = ysinx + 2x
I translated it into standard y' + P(x)y= Q(x) format as
y' - ytanx = 2x/cosx
then I needed an integrating factor, so I used
I(x)=e^{-\int tanx\:dx} = cosx
when I multiply this to both sides of y' - ytanx = 2x/cosx
it doesn't seem to do much good. I just get back to where I started, and I am not seeing anything that will wrap into a nice neat little derivative on the LHS.
Can you show me where I am going wrong? Thanks!
y' cosx = ysinx + 2x
I translated it into standard y' + P(x)y= Q(x) format as
y' - ytanx = 2x/cosx
then I needed an integrating factor, so I used
I(x)=e^{-\int tanx\:dx} = cosx
when I multiply this to both sides of y' - ytanx = 2x/cosx
it doesn't seem to do much good. I just get back to where I started, and I am not seeing anything that will wrap into a nice neat little derivative on the LHS.
Can you show me where I am going wrong? Thanks!