Solving Linear Transformation: Find F Given 3 Equations

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SUMMARY

The discussion focuses on solving a linear transformation F defined by three equations. The initial equations provided are F(1,0,0)=(1,2,3), F(1,1,0)=(0,0,1), and F(1,1,1)=(12,3,4). The user initially miscalculated F(e_3) due to an oversight in the calculation of F(e_2), which was correctly identified as (-1,-2,-2). The corrected value for F(e_3) is determined to be (12,3,3).

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Petrus
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Hello MHB,
given a linear transformation F so that this is known
$$\left\{
\begin{aligned}
\phantom{1}F(1,0,0)=(1,2,3) \\
F(1,1,0)=(0,0,1)\\
F(1,1,1)=(12,3,4)\\
\end{aligned}
\right.$$
Decide F

progress:
$$F(e_1)=(1,2,3)$$
$$F(e_2)=F(e_1)+F(e_2)-F(e_1)=(0,0,1)-(1,2,3)=(-1,-2,-2)$$
$$F(e_3)=F(e_1)+F(e_2)+F(e_3)-(F(e_1)+F(e_2))= (12,3,4)-(-1,-2,-2)=(13,5,6)$$
My $$f(e_3)$$ is wrong acording to facit and I don't understand

Regards,
$$|\pi\rangle$$
 
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Hello MHB,
I have seen what my misstake was... I forgot that $$F(e_2)=(-1,-2,-2)$$ that means $$F(e_1)+F(e_2)=(0,0,1)$$ so $$F(e_3)=(12,3,3)$$ I was not thinking clear, I did confuse this in my brain but now I see!

Regards,
$$|\pi\rangle$$
 

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