Solving Logarithmic Equation with Real Numbers: Log Problem Homework

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To solve the logarithmic equation 9^x - 5*3^x + 6 = 0, it is helpful to substitute y = 3^x, transforming the equation into a quadratic form: y^2 - 5y + 6 = 0. This quadratic can be factored easily, allowing for the determination of y values. Once the values of y are found, they can be used to solve for x by reverting back to the original substitution. The approach highlights the importance of recognizing patterns in exponential equations. Understanding this method can simplify the process of solving similar logarithmic problems.
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Homework Statement



9^x-5*3^X+6=0

Homework Equations



I have no idea how to solve this i suspect there is a theory that I am not familiar with involved.
want real numbers.

The Attempt at a Solution



i thought about moving the 6 to the otherside and doing log on both but you can't have ln(-6)
im clueless. need help thanks.
 
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9= 32 so 9x= (32)x= (3x)2.

Let y= 3x and your equation becomes y2- 5y+ 6= 0, and easily factored quadratic. Once you know y, solve 3x= y.
 
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