Solving Lorentz Transform problem using only length contraction

AI Thread Summary
The discussion centers on solving a Lorentz transformation problem using only length contraction and the constancy of the speed of light. Participants express confusion over the requirement that the time taken for light to reach the front of the rocket equals the time for the rocket to reach that point, questioning the logic behind it. Clarifications emphasize that the event of light reaching the front of the rocket is defined at the same location, thus necessitating a simultaneous time calculation. The conversation highlights the need to derive expressions for the coordinates in terms of the parameters provided, without resorting to Lorentz transformations. Overall, the focus is on understanding the relationship between the rocket's motion and the light signal's travel time.
Tubefox
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Homework Statement



A traveler in a rocket of length 2d sets up a coordinate system S' with origin O' anchored at the exact middle of the rocket and the x' axis along the rocket’s length. At t' = 0 she ignites a flashbulb at O'. (a) Write down the coordinates t'_F, x'_F, and t'_B, x'_B for the arrival of the light at the front and back of the rocket. (b) Now consider the same experiment as observed in a frame S relative to which the rocket is traveling at speed v (with S and S' arranged in the standard configuration). Use the Lorentz transformation to find the coordinates xF , t_F and xB , tB of the arrival of the two signals.

(This is the part my question is on) Repeat but do not use Lorentz transformation, just use length contraction and the fact that the speed of light is the same in every reference frame. Follow these steps:

1) Sketch the contracted rocket in the S frame at t=0. It moves with speed v.

(I did this.)

2) Write a formula for the time tF when the front of the rocket gets to xF

3) Write a formula for the time tF when the light gets to xF

4) Equate (2) and (3) to solve for xF and tF

5) Repeat for xB and tB

Homework Equations


L = \frac{L_0}{\gamma}
x=\gamma(x' + vt')
t=\gamma(t' + \frac{vx'}{c^2})

The Attempt at a Solution



Here's the prime frame measurements:

x&#039;_F=d \\<br /> t&#039;_F = \frac{d}{c}\\<br /> x&#039;_B = -d\\<br /> t&#039;_B= \frac{d}{c}

And according to the Lorentz transform equations, here's what we have for S:

x_F=\gamma d (1+\frac{v}{c})\\<br /> t_F=\frac{\gamma d}{c}(1+\frac{v}{c})\\<br /> x_B=\gamma d(\frac{v}{c}-1)\\<br /> t_B=\frac{\gamma d}{c}(1-\frac{v}{c})

That's all fine. The issue arises when I try to follow the procedure outlined in the problem statement. It appears to be nonsense. Why would it take the same amount of time for the rocket to get to x_F as it would for the light to get to x_F? Even so, how can I solve for two unknowns based on one equation? Could someone, at the very least, clarify the wording a little bit?

Thanks.
 
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Tubefox said:
That's all fine. The issue arises when I try to follow the procedure outlined in the problem statement. It appears to be nonsense. Why would it take the same amount of time for the rocket to get to x_F as it would for the light to get to x_F?
I assume that's a typo. I think you meant the front and back of the ship.

In any case, why do you think it would take the same amount of time for the light to reach the front and back of the ship as seen from the S frame? Where's your analysis using length contraction only?
 
Doc Al said:
I assume that's a typo. I think you meant the front and back of the ship.

In any case, why do you think it would take the same amount of time for the light to reach the front and back of the ship as seen from the S frame? Where's your analysis using length contraction only?

No, that is not a typo. At least not on my part.
 
Where is the front of the rocket after a time t?
Where is the light sent towards the front after time t?
What relation must be satisfied for the time when the light hits the front of the rocket?
 
Orodruin said:
Where is the front of the rocket after a time t?
x_F

Where is the light sent towards the front after time t?
Says right there in the procedure that it's at x_F

What relation must be satisfied for the time when the light hits the front of the rocket?
It's equal to the time it takes the front of the rocket to reach x_F
 
Last edited by a moderator:
You misunderstand me. Those are questions I want you to answer by giving expressions in terms of d, c, t and v.

Edit: Without using Lorentz transformations, only referring to length contraction and the speed of light being constant.

Edit 2: And the reason the light takes the same time to reach ##x_F## as the front takes is because it is defined as the point where the light catches up ...
 
Tubefox said:
No, that is not a typo. At least not on my part.
Ah, I misread what you had written.
Tubefox said:
Why would it take the same amount of time for the rocket to get to x_F as it would for the light to get to x_F?
By definition, x_F is the location of the event "light reaches front of rocket". So of course the front of the rocket and the light must be at the same location when the light reaches that point.
 
Tubefox said:
1.
That's all fine. The issue arises when I try to follow the procedure outlined in the problem statement. It appears to be nonsense. Why would it take the same amount of time for the rocket to get to x_F as it would for the light to get to x_F?
Thanks.


Where does it say that ?
 
Tubefox said:
x_F
Ah, so you're done? The answer is x_F and t_F? :smile:

Seriously, you must solve for those coordinates in terms of the given parameters (d, v, c).
 
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