Solving Matrix Multiplication: A*B^T with A=2,1;5,3 and B=1,-1,1;-1,1,1

AI Thread Summary
The discussion centers on the multiplication of matrix A by the transpose of matrix B, specifically A*B^T, where A is a 2x2 matrix and B is a 2x3 matrix. The confusion arises from the dimensions of the matrices, as the transpose of B results in a 3x2 matrix, making it impossible to multiply with A. Participants clarify that the operation cannot be performed as stated, and suggest that the intended operation might have been (AB)^T instead. The realization that the order of multiplication matters is acknowledged, leading to a better understanding of matrix operations. Ultimately, the conclusion is that A*B^T cannot be computed due to incompatible dimensions.
lagwagon555
Messages
59
Reaction score
1

Homework Statement


Find A*B^T, where A=

2 1
5 3

And B=

1 -1 1
-1 1 1


Homework Equations



n/a



The Attempt at a Solution



The problem is, is that if I get the transpose of B, I will end up with a 3x2 matrix. Isn't this impossible to multiply by a 2x2 matrix? Maybe the answers is just 'not possible', but I have a feeling I'm doing something wrong. Anybody got any pointers? Thanks!
 
Physics news on Phys.org
You are right, A*BT can't be computed. (AB)T can though, are you sure you weren't supposed to calculate that?
 
The way it was actually written was BTA, so I think it made a point of showing that it wasn't (AB)T. So I'm thinking that the answer is that it can't be computed? Thanks for the quick reply!

EDIT: ooooooooooh. Ooops. How embarassing. Of course it makes a difference when B comes first. Argh!
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top