Solving Mechanics Problem: Find Athlete's Speed & Jump Height

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The problem involves an athlete who jumps while running at a constant speed, landing 5 meters away after 1 second. To find her speed, the horizontal distance covered (5 meters) divided by the time (1 second) indicates she was running at 5 meters per second. The vertical jump height can be calculated using projectile motion equations, leading to a maximum height of 1.25 meters. The athlete's motion can be analyzed by separating horizontal and vertical components, with the vertical component affecting jump height and the horizontal component remaining constant. The solution effectively demonstrates the principles of projectile motion.
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Homework Statement


An athlete running with a constant speed jumps and lands 1 second later 5 meters from the point where she jumped. How fast was she running? How high did she jump?


Homework Equations


v=u+at, d=ut+1/2at^2

The Attempt at a Solution


I have no idea how to get started but the answers are 5 and 1.25 respectively.
 
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Once airborne, the athlete may be treated as a projectile. Use the two well-known facts about projectile motion

1. The vertical component of the initial velocity is related to maximum height and the time of flight.
2. The horizontal component of the initial velocity does not change.

Assume that when the athlete "jumps", she gives herself a push in the vertical direction only, i.e. she changes only the vertical component of her velocity from zero to something other than zero.
 
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