Solving Momentum & Energy for Particles: Masses m & 3m

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The discussion revolves around a physics problem involving two particles of masses m and 3m connected by a rigid rod on a smooth table. The heavier mass is projected with an initial velocity, and the goal is to determine the velocities of both particles when the rod is oriented north-south. Participants emphasize the application of conservation of momentum and energy principles, debating the relevance of vertical height in the energy equation. There is confusion regarding the movement of the masses, particularly whether the system can gain vertical height while remaining horizontal. Suggestions include treating the system as a compound pendulum to analyze the motion further.
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Homework Statement


Two particles of masses m and 3m are connected by a light rigid rod. The system rests on a smooth horizontal table, the heavier mass due east of the lighter mass. The heavier mass is projected with initial velocity uj. Find the velocities of the particles when the rod runs north-south.


Homework Equations


Conservation of momentum, conservation of energy.


The Attempt at a Solution


Applying conservation of momentum in the j direction, 3m(u) + m(0) = 3mv + mw.
3u = 3v + w.

Conservation of energy, 1/2(3m)u2 = 3mgh +1/2(3m)v2
u2 = 2gh + v2

I've no idea where to go from here.
This isn't homework, just a question I came across while revising for exams.
 
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Hi Maybe_Memorie! :smile:

(try using the X2 tag just above the Reply box :wink:)
Maybe_Memorie said:
… The system rests on a smooth horizontal table

Conservation of energy, 1/2(3m)u^2 = 3mgh +1/2(3m)v^2
u^2 = 2gh + v^2

erm :redface: … leave out the mgh ! :biggrin:
 
tiny-tim said:
erm :redface: … leave out the mgh ! :biggrin:

Why? The 3m mass gains vertical height.
 
Maybe_Memorie said:
Why? The 3m mass gains vertical height.

No …
Maybe_Memorie said:
Two particles of masses m and 3m are connected by a light rigid rod. The system rests on a smooth horizontal table, the heavier mass due east of the lighter mass. The heavier mass is projected with initial velocity uj. Find the velocities of the particles when the rod runs north-south.
… everything's horizontal.
 
tiny-tim said:
No …

… everything's horizontal.

The 3m mass is projected with a velocity uj, i.e. a velocity of u in the j-> direction, upwards.
 
Maybe_Memorie said:
The 3m mass is projected with a velocity uj, i.e. a velocity of u in the j-> direction, upwards.

Where I live, that's the k direction. :wink:

Anyway, if the rod starts east-west, and ends up north-south (as in the question), how can it ever move upwards??
 
tiny-tim said:
Where I live, that's the k direction. :wink:

Anyway, if the rod starts east-west, and ends up north-south (as in the question), how can it ever move upwards??

It's like the large mass moves in a circle around the small mass. So the 3m mass gains height in rotating.

It may be possible to treat it as a compound pendulum.
 
Any suggestions?
 
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