Solving Momentum Homework Questions: Q1 & Q2

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The discussion focuses on solving two momentum-related homework questions involving collisions. In the first question, a 9.0-kg ball collides with a stationary 3.0-kg ball, resulting in the first ball moving at 5.61 m/s at an angle, with the second ball's velocity calculated to be 7.7 m/s at 17° south of east. The second question involves a cue ball striking a stationary five-ball, with the cue ball's post-collision velocity determined to be 0.505 m/s at 320°. Participants emphasize the importance of applying conservation of momentum and breaking down the momentum into components for accurate calculations. Understanding these principles is crucial for solving similar physics problems effectively.
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Homework Statement



Two Questions:

1) A 9.0-kg ball is traveling to the right at 8.0 m/s until it impacts a 3.0-kg stationary ball. After the collision, the 9.0-kg ball is traveling at 5.61 m/s at an angle of 7.8º above the horizontal. Calculate the velocity of the 3.0-kg ball after the impact. (Answer: 7.7m/s 17°S of E)

2) 3. A cue ball traveling at 0.785 m/s [270°] strikes a stationary five-ball, causing it to move at 0.601 m/s [230°]. The cue ball and the five-ball each have a mass of 160g. What will be the velocity of the cue ball immediately after impact? Ignore frictional and rotational effects. (Answer: 0.505 m/s @ 320°)



Homework Equations



p=mv

The Attempt at a Solution



They seem to be similar questions.

For question 1:

p = mv

p = (9) x (8) = 72 for ball 1

p = 0 for ball two

Impact momentum = (9) x (5.61) = 50.49 kg x m/s

Impulse = 72 - 50.49?

similar situation for question 2. What is the process for solving?

I have the answers, but how do you get to them?

Question 1: (Answer: 7.7m/s 17°S of E)

Question 2: (Answer: 0.505 m/s @ 320°)
 
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Apply conservation of momentum. Hint: Since momentum is a vector, use a separate equation for each component.
 
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