Solving Motion in a Plane: Find Velocity at t=7.6s

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A particle with an initial velocity of 43.4 m/s east undergoes a constant southward acceleration of 2.3 m/s². After 7.6 seconds, its velocity is calculated to be 60.8 m/s. To determine the direction of this velocity in degrees, the tangent of the angle can be found by dividing the southward component by the eastward component. The angle should be measured anticlockwise from the east. The discussion emphasizes the importance of calculating both speed and direction for a complete understanding of the particle's motion.
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A particle experiences a constant acceleration that is south at 2.3 m/s2. At t = 0, its velocity is 43.4 m/s east. What is its velocity at t = 7.6 s?

I got 60.8 m/s but it also asks for the direction in degrees and I'm not sure how to find that.
 
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Hi tag16! Welcome to PF! :smile:
tag16 said:
I got 60.8 m/s but it also asks for the direction in degrees and I'm not sure how to find that.

Dividing the y by the x will give you the tangent of the angle

(and remember that the angle increases anticlockwise! :wink:)
 

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