Solving Multivariable Limits: Evaluating $\lim_{(x,y) \to (0,0)}\frac{x-y}{x+y}$

spacefreak
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Homework Statement


Evaluate the following limit or give a reason explaining why the limit does not exist.

\lim_{(x,y) \to (0,0)}\frac{x-y}{x+y}

Homework Equations


x = r*\cos\theta
y = r*\sin\theta

The Attempt at a Solution


\lim_{r \to 0}\frac{r*\cos\theta-r*\sin\theta}{r*\cos\theta+r*\sin\theta} =<br /> \lim_{r \to 0}\frac{\cos\theta-\sin\theta}{\cos\theta+\sin\theta} =<br /> \lim_{r \to 0}\frac{1}{1+\tan\theta} - \lim_{r \to 0}\frac{1}{1+\cot\theta}

When I get to this point, I'm stuck. How do I either find the limit or show that it doesn't exist?
 
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No need for polar coordinates on this one. Take the limit as x->0 while y=0 and vice versa.
 
So, to make sure I understand.

When x -> 0 while y = 0, the limit equals 1. When y -> 0 while x = 0, the limit equals -1. Therefore, the limit does not exist. Am I correct?

I appreciate your help.
 
spacefreak said:
So, to make sure I understand.

When x -> 0 while y = 0, the limit equals 1. When y -> 0 while x = 0, the limit equals -1. Therefore, the limit does not exist. Am I correct?

I appreciate your help.

Exactly.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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