Solving Net-Force Question: 20 kg Crate, F = 200 N

  • Thread starter Thread starter Emperor
  • Start date Start date
AI Thread Summary
To solve for the upward acceleration of a 20 kg crate lifted by a 200 N force, the net force must be calculated by considering both the lifting force and the weight of the crate. The weight of the crate is 196 N (20 kg x 9.8 m/s²). The net force acting on the crate is 200 N - 196 N = 4 N. Using the formula a = F/m, the acceleration is found to be 4 N / 20 kg = 0.2 m/s². Understanding the forces acting on the crate is crucial for accurately determining its acceleration.
Emperor
Messages
11
Reaction score
0

Homework Statement



A 20 kg crate is lifted by an upward force of 200 N. The crate's upward acceleration is:


Homework Equations



F = ma

a = F ÷ m

The Attempt at a Solution



I can't for the life of me find the answer to this question (which is supposedly .2 m/s^2). I don't know how to get an answer like that, the best I can come up with is 10 m/s^2 using the formula above. Help will be appreciated, thank you.
 
Physics news on Phys.org
What forces act on the crate?

ehild
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top