Solving net horizontal word problem

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SUMMARY

The discussion focuses on calculating the total depth and net horizontal distance of a mineshaft system involving three shafts. The first shaft descends at a 3.5-degree angle for 225 feet, followed by a vertical shaft of 125 feet, and a third shaft that descends at a 6.8-degree angle for 175 feet. The total depth below ground level at the end of the third shaft is determined by summing the vertical components of each shaft. The net horizontal distance is calculated using trigonometric functions based on the angles and lengths of the shafts.

PREREQUISITES
  • Understanding of basic trigonometry, including sine and cosine functions.
  • Familiarity with angle measurements in degrees.
  • Knowledge of vertical and horizontal distance calculations in geometry.
  • Ability to apply the Pythagorean theorem in practical scenarios.
NEXT STEPS
  • Research trigonometric functions for calculating vertical and horizontal components.
  • Learn how to apply the Pythagorean theorem in three-dimensional contexts.
  • Explore examples of similar problems involving angles and distances in mining engineering.
  • Study the principles of slope and angle measurement in construction and excavation.
USEFUL FOR

This discussion is beneficial for students and professionals in engineering, particularly those involved in mining, construction, or any field requiring spatial calculations and trigonometric applications.

dramaqueen
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the pathway for a mineshaft is described as follows: The first shaft extends north and down at an angle of 3.5 degree for 225ft to a vertical shaft which 125ft long. A third shaft then extends north and down at an angle 6.8 degree for 175ft. What is the total depth below ground level at the end of the third shaft? Also, what is the net horizontal distance from the ground opening to the end of the third shaft?

I look all over the chapter example and could figure out how to do it...

HELP!
 
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