Solving Newton's Method for xn with y as a Constant

DeadxBunny
Messages
29
Reaction score
0

Homework Statement


Identify the formula

xn+1 = -2xn + 3yxn^(2/3)

as the Newton's method for a certain function. Here y is a fixed constant. What is the limit of xn?


Homework Equations


Newton's method?:

xn+1 = xn - f(xn)/f'(xn)


The Attempt at a Solution


I don't know how to begin.

Thanks in advance!
 
Physics news on Phys.org
1st step- Newton's method gives

x_n-x_{n-1}=f(x_n)/f'(x_n)

So rearrange your equation to get f(x_n)/f'(x_n). Then think.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top