Solving Object's Motion with Constant Forces

AI Thread Summary
An object with a mass of 4.0 kg is initially moving north at 4.8 m/s but is acted upon by opposing forces of 6.5 N and 9.5 N, resulting in a net force of 3.0 N southward. The discussion focuses on calculating how far the object will travel before coming to rest and its position 2.5 seconds after that moment. The user expresses confusion about which equations to use, specifically mentioning the kinematic equation x = VoT + 1/2aT^2 and questioning its applicability due to the lack of time in part (a). Clarification is sought on how to approach the problem and apply the correct physics principles. Understanding the net force and its impact on motion is crucial for solving the problem effectively.
papa_smurf493
Messages
30
Reaction score
0

Homework Statement



An object with a mass of 4.0 kg travels with a constant velocity of 4.8 m/s northward. It is then acted on by a force of 6.5 N in the direction of motion and a force of 9.5 N to the south, both of which continue even after the mass comes momentarily to rest.

(a) How far will the object travel before coming to rest?


(b) What will be its position 2.5 s after the object comes momentarily to rest?


Homework Equations





The Attempt at a Solution


I have 4.0 Kg traveling in one direction and a 3.0 N force (9.5N-6.5N=3.0N) being applied in the other direction. Soon the car will come to a stop and start to accelerate in the forward direction. Plug in the initial conditions of 4.0Kg traveling North at 4.8 m/s being acted upon by a constant 3.0N (Kg/ms^2) south force. (North is usually up and is positive; so a Southern acting force is negative).

I like to reword the question so its relevant to me, but we just started this stuff and i need some help with the equations that i will need to use.
 
Physics news on Phys.org
please i have no idea where to start and what equation to use!
 
ok i tried using x=VoXT + 1/2axt^2 but i don't think it applies because there is no time involved in part a
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Motion of an Object: Displacement & Average Velocity
Replies
8
Views
2K
Work Pulley Problem with constant speed
Replies
2
Views
984
Equilibrium of Forces and Torques on Sawhorses Supporting a Person on a Board
Replies
6
Views
2K
Circular motion/ speed increases at a constant rate
Replies
7
Views
2K
Coriolis Force and Centrifugal Force
Replies
21
Views
2K
What is the energy conservation principle in a two masses and pulley problem?
Replies
33
Views
4K
Resistance force changing the velocity of an object
Replies
8
Views
1K
Circular motion — the acceleration is not constant?
Replies
1
Views
1K
Please explain the action of forces here
Replies
8
Views
2K
Circular Motion With Constant Angular Acceleration
Replies
3
Views
2K

Hot Threads

Recent Insights

Back
Top