Solving ODE involving square of first derivative

Click For Summary
SUMMARY

The discussion centers on solving a non-linear ordinary differential equation (ODE) derived from Gregory's classical mechanics book, specifically problem 2.10. The ODE is expressed as \(\dot{r}^{2}=\frac{u^{2}}{a^{2}}(\frac{U^{2}a^{2}}{a^{2}}-r^{2})\), where \(u\), \(U\), and \(a\) are constants representing unit speed, speed, and length, respectively. The solution involves transforming the equation to \(\dot{r}=\pm\frac{u}{a}\sqrt{U^{2}-r^{2}}\) and integrating using the substitution \(r=U\sin\alpha\). This method effectively addresses the integration challenge posed by the non-linear nature of the ODE.

PREREQUISITES
  • Understanding of ordinary differential equations (ODEs)
  • Familiarity with integration techniques, particularly trigonometric substitutions
  • Knowledge of classical mechanics principles related to motion
  • Basic algebra skills for manipulation of equations
NEXT STEPS
  • Study advanced techniques for solving non-linear ODEs
  • Explore trigonometric substitution methods in calculus
  • Learn about the physical interpretations of ODEs in classical mechanics
  • Practice solving similar problems from Gregory's classical mechanics book
USEFUL FOR

Students and enthusiasts of classical mechanics, mathematicians focusing on differential equations, and anyone seeking to enhance their problem-solving skills in non-linear dynamics.

tsw99
Messages
33
Reaction score
0

Homework Statement



this is not from a math course, but from Gregory's classical mechanics book prob 2.10
it's easy to obtain the desired ODE
[tex]\dot{r}^{2}=\frac{u^{2}}{a^{2}}(\frac{U^{2}a^{2}}{a^{2}}-r^{2})[/tex]
since it's non-linear, i have a difficult time to solve for r(t)
u, U and a are some constants with unit speed, speed and length resp.

Homework Equations





The Attempt at a Solution


all methods i know fail, I believe there is some trick that I am not aware of. great appreciate for any help:(
 
Physics news on Phys.org
The equation you have can be written as:
[tex] \dot{r}=\pm\frac{u}{a}\sqrt{U^{2}-r^{2}}[/tex]
Dividing and integrating shows that:
[tex] \int\frac{dr}{\sqrt{U^{2}-r^{2}}}=\pm\frac{u}{a}\int dt[/tex]
The integral can be solved by the substitution:
[tex] r=U\sin\alpha[/tex]
I will leave you to slog through the algerbra.
 
hunt_mat said:
The equation you have can be written as:
[tex] \dot{r}=\pm\frac{u}{a}\sqrt{U^{2}-r^{2}}[/tex]
Dividing and integrating shows that:
[tex] \int\frac{dr}{\sqrt{U^{2}-r^{2}}}=\pm\frac{u}{a}\int dt[/tex]
The integral can be solved by the substitution:
[tex] r=U\sin\alpha[/tex]
I will leave you to slog through the algerbra.

oh...thank you very much!
I think i need to brush up my math skills...edit: in fact i type the ODE wrongly, but the method should be similar
 
Last edited:

Similar threads

Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
Replies
9
Views
3K
Replies
4
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
7
Views
2K
Replies
3
Views
2K
Replies
9
Views
2K