Solving Parabolic Coordinates Homework: Find x,y; Show Kinetic Energy

  • Thread starter Thread starter metgt4
  • Start date Start date
  • Tags Tags
    Coordinates
Click For Summary
SUMMARY

The discussion centers on solving a homework problem involving parabolic coordinates defined by the equations η = (x² + y²)¹/² - x and ξ = (x² + y²)¹/² + x. The objective is to express x and y in terms of ξ and η, and subsequently derive the kinetic energy formula T = (m/8)(ξ + η)(ξ'²/ξ + η'²/η) for a particle of mass m. The original poster, Andrew, initially struggled with the conversion of coordinates but later resolved the issue independently.

PREREQUISITES
  • Understanding of parabolic coordinates and their definitions
  • Familiarity with kinetic energy formulas in classical mechanics
  • Knowledge of calculus, specifically derivatives and their applications
  • Ability to manipulate algebraic expressions involving multiple variables
NEXT STEPS
  • Research the derivation of kinetic energy in different coordinate systems
  • Study the transformation between Cartesian and parabolic coordinates
  • Explore applications of parabolic coordinates in physics problems
  • Learn about the implications of coordinate transformations on physical quantities
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and coordinate systems, as well as educators looking for examples of coordinate transformations in problem-solving.

metgt4
Messages
34
Reaction score
0

Homework Statement


(ξ,η) in a plane are defined by η = (x2 + y2)1/2 - x and ξ = (x2 + y2)1/2 + x

Find x and y in terms of ξ and η. Show that the kinetic energy of a particle of mass m is:

T = (m/8)(ξ + η)(ξ'2/ξ + η'2/η)


The Attempt at a Solution



My attempt is scanned and appended in this post. I found x and y in terms of η and ξ, but am not sure where to go from there in order to find the kinetic energy in terms of the two. If somebody could point me in the right direction, I'd really appreciate it.

Thanks!
Andrew
 

Attachments

  • scan0004.jpg
    scan0004.jpg
    7.3 KB · Views: 480
Physics news on Phys.org
Nevermind, got it figured out. I went wrong in finding x and y as well.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 55 ·
2
Replies
55
Views
8K